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Complete the proof of the Law of Sines/Cosines.
Given triangle ABC with altitude segment AD labeled x. Angles ADB and CDA are _____1._____ by the definition of altitudes, making triangle ABD and triangle CDA right triangles. Using the trigonometric ratios sine of B equals x over c and sine of C equals x over b. Multiplying to isolate x in both equations gives x = _____2._____ and x = b β‹… sinC. We also know that x = x by the reflexive property. By the substitution property, _____3._____. Dividing each side of the equation by bc gives: sine of B over b equals sine of C over c.
1. altitudes
2. b β‹… sinB
3. b β‹… sinB = c β‹… sinC

1. right angles
2. b β‹… sinB
3. b β‹… sinB =c β‹… sinB

1. altitudes
2. c β‹… sinB
3. c β‹… sinB = b β‹… sinC

1. right angles
2. c β‹… sinB
3. c β‹… sinB = b β‹… sinC

Will give brainliest to whoever solves this for me Complete the proof of the Law of SinesCosines Given triangle ABC with altitude segment AD labeled x Angles AD class=

Respuesta :

Answer:

1. right angles

2. c β‹… sinB

3. c β‹… sinB = b β‹… sinC

Step-by-step explanation:

I got this question too and I guessed it and it was correct

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