The slope of the given segment is m = Δy/Δx = (-1 -(-3))/(0 -4) = 2/-4 = -1/2
The midpoint of the given line is (S +T)/2 = ((4, -3) +(0, -1))/2 = (4/2 -4/2) = (2, -2)
The slope of the perpendicular line is -1/m = -1/(-1/2) = 2
So, in point-slope form, the equation of the perpendicular bisector is y -k = m(x -h) . . . . . . line with slope m through point (h, k) y +2 = 2(x -2) This can be rearranged to any of several forms: y = 2x -6 . . . . . . slope-intercept form 2x -y = 6 . . . . . . standard form
