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  • 15-12-2015
  • Mathematics
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find two consecutive numbers whose squares differ by 17

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calculista
calculista calculista
  • 23-07-2018

Let

x---------> the first number

x+1------> the second number


we know that

[tex] (x+1)^{2} -x^{2} =17\\ x^{2} +2x+1-x^{2} =17\\ 2x+1=17\\ 2x=16\\ x=8 [/tex]

so

[tex] x=8\\ x+1=9 [/tex]


therefore


the answer is

the numbers are

[tex] 8,9 [/tex]

Answer Link

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