anigallegos anigallegos
  • 13-10-2017
  • Mathematics
contestada

Solve for x over the complex numbers. x2+10x+41=0

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anaguzman
anaguzman anaguzman
  • 13-10-2017
The correct answer is X= -5±41
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ejelonubenedict
ejelonubenedict ejelonubenedict
  • 13-10-2017
x²+10x+41=0
using x=(-b±√b²-4ac)½
where a= 1
b=10
c=41

x= (-10±√10²-4×1×41)½
x=-5 ± √(100-164)
x=-5±√(-64)½
x=-5±4i
x=-5+4i or -5-4i
where i= √-1
Answer Link

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