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An electron is ejected horizontally at a speed of 1.5 ✕ 106 m/s from the electron gun of a computer monitor. if the viewing screen is 35 cm away from the end of the gun, how far will the electron travel in the vertical direction before hitting the screen?

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meerkat18
GivenHorizontal velocity, vxi = 1.5 *10^6 m/sDistance ,x =0.35 mFirst we will calculate the time takenx = vxi t0.35 m = (1.5 *10^6 m/s) tt =0.23 *10^-6 sThe vertical distance travelled by the electron isy =1/2 gt^2= 0.5 *9.8 m/s^2 *(0.23 *10^-6 s)^2= 0.25 *10^-12 m

Therefore, the answer is 0.25 *10^-12 m

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