The factor theorem of algebra states that if a polynomial, P(x), is divided by x−a, then the remainder is P(a). Verify the remainder theorem by showing that when x^2−2x−16
is divided by x+3 the remainder is the same as P(−3).
Remainder for (x^2−2x−16)/(x+3)?
P(-3)?
okay... by using long division method first we have x²-2x-16 ÷ x+3 quotient = x-5 , remainder = -1 using factor Theorem we have f(-3) = (-3)² -2(-3) -16 = 9+6-16 = -1 (remainder)
