Respuesta :

mreijepatmat
1st Problem:

2r≤ 3r - 8
2r - 3r ≤ - 8
- r ≤ - 8 and r≥8, then the solution is {8,9,10}

2nd Problem

16 - r ≤ 8
-r ≤ 8 -16
-r ≤ - 8  and r≥8, then the solution is {8,9,10}