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A basketball referee tosses the ball straight up for the starting tip-off. at what velocity (in m/s) must a basketball player leave the ground to rise 1.32 m above the floor in an attempt to get the ball? m/s â

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Respuesta :

For this analysis,
g = 9.8 m/s²
Wind resistance is ignored.
All quantities are measured positive upward.

h = 1.32 m, the vertical height

Let u = vertical launch velocity of the basketball player.
At the maximum height of 1.32 m, the vertical velocity is zero.
Therefore
u² - 2gh = 0
u² = 2gh = 2*9.8*1.32 = 25.872
u = 5.0865 m/s

Answer:  5.1 m/s (nearest tenth)

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