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What is the stopping distance if the car is initially traveling at speed 8.0v? assume that the acceleration due to the braking is the same in both cases?

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Respuesta :

meerkat18
The distance for any rectilinear motion at constant acceleration is:

d = v₀t + 0.5at²
where
v₀ is the initial velocity

So, if v₀ = 8v, and it stopped to 0 m/s, then the acceleration is equal to:
a = (0 - 8v)/t = -8v/t
Thus,
d = (8v)(t) + (0.5)(-8v/t)(t²)
d = 8vt - 4t
d = 4t(2v - 1)

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