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Now we look at the electron configuration of ions. Give the abbreviated electron configuration for each
Be:
Sn:
Be:
F:
F:
Ti:
Sn2:
Sn+:
As:
AsĀ³:
TiĀ²+:
AsĀ³+:
Ti:
As
K:
Zn:
K:
0%
Mg2:
Now go
Zn2+:
Ca2+:
Cr:
back through this lab and consider all the atoms and/or ions that are in the same box. Place a star
by the atom or ion that you think has the largest radius of those options.

Now we look at the electron configuration of ions Give the abbreviated electron configuration for each Be Sn Be F F Ti Sn2 Sn As As Ti As Ti As K Zn K 0 Mg2 Now class=
Relax

Respuesta :

Answer:

Sure, here are the abbreviated electron configurations for each:

- Be: 1sĀ² 2sĀ²

- Sn: [Kr] 5sĀ² 4dĀ¹ā° 5pĀ²

- Be: 1sĀ² 2sĀ²

- F: 1sĀ² 2sĀ² 2pāµ

- F: 1sĀ² 2sĀ² 2pāµ

- Ti: [Ar] 4sĀ² 3dĀ²

- SnĀ²āŗ: [Kr] 4dĀ¹ā°

- Snāŗ: [Kr] 4dĀ¹ā° 5sĀ²

- As: [Ar] 4sĀ² 3dĀ¹ā° 4pĀ³

- AsĀ³āŗ: [Ar] 3dĀ¹ā°

- TiĀ²āŗ: [Ar] 3dĀ²

- AsĀ³āŗ: [Ar] 3dĀ¹ā°

- Ti: [Ar] 4sĀ² 3dĀ²

- As: [Ar] 4sĀ² 3dĀ¹ā° 4pĀ³

- K: [Ar] 4sĀ¹

- Zn: [Ar] 3dĀ¹ā° 4sĀ²

- K: [Ar] 4sĀ¹

- MgĀ²āŗ: [Ne] 3sĀ²

- ZnĀ²āŗ: [Ar] 3dĀ¹ā°

- CaĀ²āŗ: [Ar] 4sā°

- Cr: [Ar] 4sĀ¹ 3dāµ

Now, going back through the list and marking the atom or ion with the largest radius:

- Be: *

- Sn:

- Be: *

- F:

- F:

- Ti:

- SnĀ²āŗ:

- Snāŗ:

- As:

- AsĀ³āŗ:

- TiĀ²āŗ:

- AsĀ³āŗ:

- Ti:

- As:

- K: *

- Zn:

- K: *

- MgĀ²āŗ:

- ZnĀ²āŗ:

- CaĀ²āŗ:

- Cr: *

The atoms or ions with a star (*) next to them are the ones that are likely to have the largest radius among the options listed.

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