Relax

Respuesta :

[tex]\bf \begin{array}{rlclll} (-5&,&-180^o)\\ \uparrow &&\uparrow \\ r&&\theta \end{array}\quad \begin{cases} x=rcos(\theta )\\ \qquad -5\cdot cos(-180^o)\\ \qquad -5\cdot -1\\ \qquad 5\\ ----------\\ y=rsin(\theta )\\ \qquad -5\cdot sin(-180^o)\\ \qquad -5\cdot 0\\ \qquad 0 \end{cases}\implies (5,0)[/tex]