SpeedyGonzalez
SpeedyGonzalez
11-06-2017
Mathematics
contestada
math radicals question
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mspeople
mspeople
11-06-2017
Let's find the factors of 32 and 72:
32=2*4*4 72=6*6*2
Therefore both of the radicals can be simplified into [tex]16 \sqrt{2} [/tex] and [tex]12 \sqrt{2} [/tex]. Now adding them we get [tex]28 \sqrt{2} [/tex]
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irspow
irspow
11-06-2017
4√32+2√72
4√(2*2*2*2*2)+2√(2*2*2*3*3)
4√(16*2)+2√(4*9*2) moving out all of the perfect squares...
4*4√2+2*2*3√2
16√2+12√2
(16+12)√2
28√2
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