consider the following secret method. public double secret(int x, double y) which of the following lines of code, if located in a method in the same class as secret, will compile without error?

The correct option: double result = secret(4, 4.0); is lines of code will successfully compile if they are placed in a method of the same class as secret.

Explain the term compiling?

When creating a Java program, the text that can be read by programmers is converted into bytecodes, that are platform-independent commands for the Java Virtual Machine (JVM).

As explained in the following method-

public double secret(int x, double y)

{

return x/2.0;

}

This function's return type is double, so any variable where the result will be stored should also have a double type.

The right choice, therefore, is double result = secret(4, 4.0);

All other choices are false and will result in an error.

for instance:

secret(4, 4); int result;

While you pass all integer variables, the function secret in it only accepts the first integer plus second double inputs.

int result = secret(4, 4.0);

Double values are not permitted to be stored in integer.

In the formula double result = secret(4.0, 4.0), you are giving the wrong kind of argument.

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The complete question is-

Consider the following method.

public double secret(int x, double y) { return x/2.0; }

Which of the following lines of code, if located in a method in the same class as secret, will compile without error?

int result = secret(4, 4);

double result = secret(4.0, 4);

int result = secret(4, 4.0);

double result = secret(4.0, 4.0);

double result = secret(4, 4.0);