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Fiber optics are an important part of our modern internet. In these fibers, two different glasses are used to confine the light by total internal reflection at the critical angle for the interface between the core (ncore = 1.512 ) and the cladding (ncladding = 1.445). 1- Numerically, what is the largest angle (in degrees) a ray will make with respect to the interface of the fiber θmax, and still experience total internal reflection? 2- Suppose you wanted the largest angle at which total internal reflection occurred to be θmax = 5 degrees. What index of refraction does the cladding need if the core is unchanged?

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The angle of refraction is 73.88°, angle of cladding is 1.496.

What is angle of refraction ?

Angle formed at the point of refraction between two media between a refracted ray and a line parallel to the surface.

What is critical angle?

The maximum angle at which a light beam traversing a transparent media can collide with a barrier separating that medium from a second one having a lower refractive index without being completely reflected inside the first medium.

calculate the critical angle for this combustion

n care sin∅i = n cladding sin∅ r

∅i = incident angle

∅r = angle of refraction

For T₁R: Qr= 90°, sin∅r= 1

Qc= sin -1 ( n cladding/ n care) = sin -1 ( 1.443/1.502)

Qc= 73.88°

total this is angle with normal, angle with interface is :

∅ = (90-73.88)

= 16.12°

if ∅ max = 5°

∅max+ ∅c = 90°

∅c = 90°-∅max = 85°

Sin 85°= n cladding/ n care

ncladding = 1.502* sin85°

= 1.496

Therefore, the angle of refraction is 73.88°, angle of cladding is 1.496.

Learn more about angle of refraction from the given link.

https://brainly.com/question/16496110

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