76.9kg male and 44.4kg female pair figure skating team gliding across the ice at 7.26 m/s preparing for a throw jump maneuver. The male skater tosses the female skater forward with a speed 8.83 m/s . Determine the speed of male skater after the throw .

The relationship between a particle's mass and velocity is called momentum. Being a vector quantity, momentum possesses both magnitude and direction.

Given that 76.9kg male and 44.4kg female pair figure skating team gliding across the ice at 7.26 m/s.

the female skater is tossed forward with a speed 8.83 m/s .

Let the speed of male skater after the throw = v m/s.

From principle of conservation of momentum,

Total initial momentum = total final momentum

⇒ (76.9 + 44.4) × 7.26 = 76.9×v + 44.4×8.83

⇒ 76.9×v = (76.9 + 44.4) × 7.26 - 44.4×8.83

⇒ v = 6.35 m/s.

Hence, the speed of male skater will be 6.35 m/s.

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