a flat loop of wire consisting of a single turn of cross-sectional area 7.50 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 t to 1.70 t in 1.00 s. what is the resulting induced current if the loop has a resistance of 2.90 ?

A magnetic field is a vector subject that describes the magnetic having an impact on transferring electric fees, electric currents, and magnetic substances. A shifting charge in a magnetic field experiences a pressure perpendicular to its very own velocity and to the magnetic field.

Calculation:-

Induced EMF E = - dφ/dt = - N * A * dB/dt

here no. of turns N = 1

change in magnetic field dB = B2 - B1

= 2.50 T - 0.500 T

= 2.00 T

Corresponding time dt = 1.00 s

Area of loop A = 8.00 cm2 = 8.00 * 10-4 m2

E = - 1 * 8.00 * 10-4 * 2.00 / 1.00

= - 1.60 * 10-3 V

= - 1.60 mV

- ve sign can be discarded as it indicates direction only.next step

b. Current I = E / R

= 1.60 mV / 2.00 Ω

= 0.80 mA

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