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A boy wants to throw a can straight up and then hit it with a second can. He wants the
collision to occur 4.0 m above the throwing point. In addition, he knows that the time
he needs between throws is 3.0 s. Assuming he throws both cans with the same speed,
What must the initial speed be?

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Respuesta :

onyebuchinnaji

The initial speed of the boy's thrown is determined as 16.03 m/s.

Initial speed of the boy's throw

The initial speed of the throw is calculated as follows;

h = vt - ¹/₂gt²

4 = 3t - (0.5)(9.8)(3)²

4 = 3t - 44.1

3t = 48.1

t = 48.1/3

t = 16.03 m/s

Thus, the initial speed of the boy's thrown is determined as 16.03 m/s.

Learn more about initial speed here: https://brainly.com/question/24493758

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