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A stone is dropped from rest into a well. The sound of the splash is heard exactly 2.70 s later. Find the depth of the well if the air temperature is 11.0°C.

Respuesta :

The depth of the well at the given air temperature is 456.3 m.

Depth of the well

The depth of the well is calculated from the principle of echo.

v = 2d/t

2d =  vt

d = vt/2

where;

  • v is speed of sound in air at  11.0°C = 338 m/s

d = (338 x 2.7)/2

d = 456.3 m

Thus, the depth of the well at the given air temperature is 456.3 m.

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