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In a reaction between iron(II) sulfide and oxygen, iron(III) oxide and
sulfur dioxide are produced. How many moles of O₂ is required to
produce 7.66 moles of Fe₂O3?
4FeS + 70₂ + 2Fe₂O3 + 4S02
a 26.81 moles
b 2.17 moles
c 7.60 moles
d None of the above

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Medunno13

Answer:

26.81 moles

Explanation:

From the coefficients of the equation, we know that for every 2 moles of iron(III) oxide produced, 7 moles of oxygen are consumed.

So, the answer is 7.66(7/2), which is 26.81 mol.

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