P 15 atm
Vâ = 12x103 m3 -3 3 Vâ = 12x10 m" Tâ = 25°c T= 28815 K
Pâ = 1.52x10 Pa
Now, Finel quantities, Tâ = 35°C = 308.15 °K
V2= 851 = -3 3
Now
by ideal gas equation
P2Y2 T2
= PV, T2
1152 X106 x 12x16 3 x 308115 8,5Ă103 x 288,15 = Pa
=
21294Ă10 Pa
Pâ = 21264 Atm
final
pressure will be
21264 Adm.
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