Solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined if the solution is extraneous or not.

The square root of the quantity 2 x minus 7 end quantity equals 1.

Relax

Respuesta :

Answer:

Solve for x , 1xβ€‰βˆ’β€‰2+1x + 2=4(xβ€‰βˆ’β€‰2)(x + 2) .

1xβ€‰βˆ’β€‰2+1x + 2=4(xβ€‰βˆ’β€‰2)(x + 2)

(xβ€‰βˆ’β€‰2)(x + 2)(xβ€‰βˆ’β€‰2)+(xβ€‰βˆ’β€‰2)(x + 2)(x + 2)=4(xβ€‰βˆ’β€‰2)(x + 2)(xβ€‰βˆ’β€‰2)(x + 2)

(xβˆ’2)+(x+2)=4

2x=4

x=2

But 2 is excluded from the domain of the original equation because it would make the denominator of one of the fractions zero--and division by zero is not allowed! Β . Β Therefore, it cannot be a root of the original equation. Β So, 2 is an extraneous solution. So, the equation has no solutions.

Step-by-step explanation: