contestada

What is the energy of a photon with a frequency of 3. 6 × 1015 hz? planck’s constant is 6. 63 × 10–34 j•s.

Relax

Respuesta :

Answer:

2.029×10^-18 J

Explanation:

E=hv

so

E=(3.06×10^15)*(6.63×10^-34)

E=2.029×10^-18 J