Respuesta :
The maximum mass of anhydrous zinc chloride that could be obtained from the products of the reaction is 8.18 g
Stoichiometry
From the question, we are to determine the maximum mass of anhydrous zinc chloride that could be obtained
From the given balanced chemical equation,
ZnO + 2HCl → ZnCl₂ + H₂O
This means 1 mole of ZnO will completely react with 2 moles of HCl to produce 1 mole of ZnClâ‚‚ and 1 mole of Hâ‚‚O
From the given information
Number of moles of ZnO = 0.0830 mole
Now, we will calculate the number of moles of HCl that is present
Volume of HCl added = 100 cm³ = 0.1 dm³
Concentration of the HCl = 1.20 mol/dm³
Using the formula,
Number of moles = Concentration × Volume
Number of moles of HCl present = 1.20 × 0.1 = 0.120 mole
Since
1 mole of ZnO will completely react with 2 moles of HCl to produce 1 mole of ZnClâ‚‚
Then,
0.06 mole of ZnO will react with the 0.120 mole of HCl to produce 0.06 mole of ZnClâ‚‚
Therefore, maximum number of moles of anhydrous zinc chloride that could be produced is 0.06 mole
Now, for the maximum mass that could be produced
Using the formula,
Mass = Number of moles × Molar mass
Molar mass of ZnClâ‚‚ = 136.286 g/mol
Then,
Mass = 0.06 × 136.286
Mass = 8.17716 g
Mass ≅ 8.18 g
Hence, the maximum mass of anhydrous zinc chloride that could be obtained from the products of the reaction is 8.18 g
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