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On a standardized exam, the scores are normally distributed with a mean of 300 and a standard deviation of 20. Find the z-score of a person who scored 302 on the exam.

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Respuesta :

LammettHash

Subtract the given score x from the mean µ and divide it by the standard deviation σ :

z = (x - µ) / σ = (302 - 300) / 20 = 0.1

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