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A balloon holds 20.0 L of helium at 10 degree Celsius. If the temperature doubles, and the pressure does not change, what will be the new volume of the balloon? Using Charles's Law
Please help!

Relax

Respuesta :

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 2 x 20.0/ 1

V2 = 40 L