A man left 1⁄2 of his property to his wife 1/3 of the remainder to his eldest
son and the rest to be divided equally among his five younger children,
each of whom got p60,000. How much did his wife get?

Relax

Respuesta :

Answer: p800,000

Step-by-step explanation:

1/2         to wife

1/3         to eldest son, and

Rest(x)   to 5 youngest children

(1/2) + (1/3) + x = 1  [The sum of the shares will equal 1 estate]

(3/6) + (2/6) + x = 1

(5/6) + x = 1

x = (1/6); to be divided among the 5 youngest children

We find that each young child receives p60,000.  That group of five received 5*(60,000) = p300,000, which represents (1/6) of the total estate (Estate).

We can write:    (1/6)*(Estate) = p300,000

Estate = p1,800,000

The wife hauled in 1/2 of this, so she received p800,000.