skylarmiller12204 skylarmiller12204

11-11-2021
Mathematics

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What are the zeros of the function
f(x)=x^2+2x-8

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profereyes12122 profereyes12122

11-11-2021

Answer:

-4, 2 (-4,0) (2,0)

Step-by-step explanation:

factoring in binomials

[tex](x+4)(x-2)=x^{2} +2x-8[/tex]

The zeros:

[tex]x+4=0\\x=0-4\\x_{1} =-4[/tex]

[tex]x-2=0\\x=0+2\\x_{2} =2[/tex]

I hope this help you

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