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A bowling ball with a radius of 15.0 cm travels down the lane so that its center of mass is moving at 3.60 m/s. The bowler estimates that it makes about 7.50 complete revolutions in 2.00 seconds. Is it rolling without slipping?

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Answer:

v = w R    where w is the angular speed of the bowling ball

v = 2 pi F R       speed of external point of ball due to spin

v = 2 pi (7.5 / 2 sec) 15 cm = 353 cm/sec = 3.5 m/s

V = 3.6 m/s     speed given for CM (also speed of external point)

one would conclude that within experimental error the ball is rolling without slipping

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