What is the element of lowest atomic number whose electronic configuration has four completely filled p sub shells

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13-10-2021
Chemistry

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What is the element of lowest atomic number whose electronic configuration has four completely filled p sub shells

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adioabiola adioabiola · Answer 1 · 2021-10-15T17:08:03+02:00

The element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe with electron configuration:1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.

According to the question, we are required to identify the element with the lowest atomic number whose electronic configuration has four completely filled p sub-shells.

Evidently, the shell with energy level one has no p orbital.

Therefore, the existence of p orbitals in electron configuration begins with shell energy level, n=2.

However, we must know that the p-orbital comprises of 3 sub-orbitals namely;

p(x) , p(y) and p(z) with two electrons of opposing spin in each sub orbital.

Therefore, the total number of electrons in the p orbital is 6 electrons.

In essence, the element in question should have electron configuration;

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.

The electron configuration above contains 54 electrons and has atomic number, 54.

In essence, the element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe.

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