havynn61 havynn61

13-09-2021
Mathematics

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13-09-2021

Answer:

m‹EFG = m‹EFH + m‹HFG

• substitute:

[tex]130 \degree = 86 \degree + m \angle HFG \\ \\ m \angle HFG = 130 \degree - 86 \degree \\ \\ { \boxed{ \: \: m \angle HFG = 44 \degree}}[/tex]

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