Sadrra Sadrra
  • 11-09-2021
  • Mathematics
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HELP
if a+1 is divisible by 3 prove that 4+7a is divisible by 3 too

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freckledspots freckledspots
  • 11-09-2021

Answer:

Step-by-step explanation:

Assume there exists integer k such that 3k=a+1.

4+7a

=7a+4

=7(a+1)-3

=7(3k)-3

=3(7k-1)

This implies that if there exists integer k such that 3k=a+1 then there is integer 7k-1 such that 3(7k-1)=4+7a

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