Air is about 78.0% nitrogen molecules and 21.0% oxygen molecules. Several other gases make up the remaining 1% of air molecules.
Part A
What is the partial pressure of nitrogen in air at atmospheric pressure (1 atm)? Assume ideal behavior.
Express your answer to three significant figures and include the appropriate units.
Part B
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Part C
What is the partial pressure of oxygen in air at atmospheric pressure (1 atm)? Assume ideal behavior.
Express your answer to two decimal places and include the appropriate units.

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Answer:

For A: The partial pressure of nitrogen in air is 0.780 atm

For C: The partial pressure of oxygen in air is 0.210 atm

Explanation:

Raoult's law is the law that is used to calculate the partial pressure of the individual gases present in the mixture.

The equation for Raoult's law is given as:

[tex]p_A=\chi_A\times p_T[/tex]                  .....(1)

where,

[tex]p_A[/tex] = partial pressure of component A in the mixture

[tex]p_T[/tex] = total partial pressure of the mixture

[tex]\chi_A[/tex] = mole fraction of A

  • For A:

We are given:

% composition of nitrogen in air = 78.0 %

[tex]\chi_{N_2}=0.780\\\\p_T=1atm[/tex]

Putting values in equation 1, we get:

[tex]p_{N_2}=0.780\times 1atm\\\\p_{N_2}=0.780atm[/tex]

Hence, the partial pressure of nitrogen in air is 0.780 atm

  • For C:

We are given:

% composition of oxygen in air = 21.0 %

[tex]\chi_{O_2}=0.210\\\\p_T=1atm[/tex]

Putting values in equation 1, we get:

[tex]p_{O_2}=0.210\times 1atm\\\\p_{O_2}=0.210atm[/tex]

Hence, the partial pressure of oxygen in air is 0.210 atm