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Answer:
Step-by-step explanation:
The distance from the cheetah's starting point (in feet) can be modeled by ...
 for the cheetah
 c = 102.6t
 for the gazelle
 g = 73.3t +500
When these are equal, the cheetah will have caught the gazelle:
 c = g
 102.6t = 73.3t +500
 29.3t = 500
 t = 500/29.3 ≈ 17.1 . . . . . . seconds
The distance at that time is ...
 c = 102.6(17.0648) ≈ 1750.9 . . . . feet
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Additional comment
The cheetah can maintain top speed only for about 10 seconds. At 500 ft distance, the gazelle is pretty safe.