Answer:
v = 3.89 m / s
Explanation:
For this exercise let's use the concept of conservation of mechanical energy
starting point. In the highest part of the mountain
     Em₀ = U = m g h
final point. In the lower part
     Em_f = K = ½ m v²
how energy is conserved
     Em₀ = Em_f
     mgh = ½ m v²
     v = [tex]\sqrt{ 2gh}[/tex]
let's use trigonometry to find the height
     sin θ = h / L
     h = L sin θ
we substitute
     v = [tex]\sqrt{ 2g L \ sin tea}[/tex]
let's calculate
     v = [tex]\sqrt{2 \ 9.8 \ 1.7 \ sin 27}[/tex]
     v = 3.89 m / s
