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A130 kg uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. Calculate the magnitude of the vertical component of the force that the wall exerts on the left end of the beam if the angle between the cable and horizontal is 41 degrees

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Respuesta :

Answer:

F_y = 147 N

Explanation:

For the beam to be in equilibrium, it must comply with the conscious and translational and rotational equilibrium.

Let's fix a reference system at the point where the cable is and make the counterclockwise rotations positive

                   ∑ τ = 0

                   -F_y x + W x / 2 + Ty 0 = 0

                   F_y  x = W x / 2

                   F_y = W / 2

                   F_y = mg / 2

                   F_y = 30 9.8 / 2

                   F_y = 147 N

directed in vertical direction

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