Three vector are oriented as shown in figure below where. A=20.0units, B=40.0units, And C=30.0. (a) The x and Y component of the resultant vector. (b) The magnitude of the resultant vector. (c) Direction of the resultant vector { please help me}

Question

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Respuesta :

eudora eudora · Answer 1 · 2021-03-19T17:53:25+01:00

Answer:

Explanation:

a). Vertical component of vector B = Bsin(45)

= 40sin(45°)

= 28.28 units

Horizontal component of vector B = Bcos(45°)

= 40cos(45°)

= 28.28 units

Vertical component of vector C = Csin(45°)

= 30sin(45°)

= 21.21 units

Horizontal component of vector C = Ccos(45°)

= 30cos(45°)

= 21.21 units

Vertical forces = A + Bsin(45°) - Csin(45°)

= 20 + 28.28 - 21.21

= 27.07

Horizontal forces = Bcos(45°) + Ccos(45°)

= 28.28 + 21.21

= 49.49 units

b). Magnitude of resultant force = [tex]\sqrt{(27.07)^2+(49.49)^2}[/tex]

= [tex]\sqrt{3182.045}[/tex]

= 56.41 units

c). Direction of the resultant force → Along vector B (at an angle of 45° from the horizontal line)