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A 95-kg astronaut is stranded from his space shuttle. He throws a 2-kg hammer away from the shuttle with a velocity of 19 m/s. How fast will he be propelled toward the shuttle, in m/s? (Round your answer to one decimal place if necessary.)

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Answer:

The astronaut will be propelled towards the shuttle at the rate of 0.4 m/s.

Explanation:

Given;

mass of Ā the astronaut, mā‚ = 95 kg

mass of the hammer thrown, mā‚‚ = 2 kg

velocity of the hammer, vā‚‚ = 19 m/s

let the recoil velocity of the shuttle = vā‚

Apply the principle of conservation of linear momentum;

mā‚vā‚ = mā‚‚vā‚‚

vā‚ = mā‚‚vā‚‚/mā‚

vā‚ = (2 x 19) / 95

vā‚ = 0.4 m/s

Therefore, the astronaut will be propelled towards the shuttle at the rate of 0.4 m/s.

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