kingduke12285 kingduke12285

12-03-2021
Mathematics

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factor y^3-1 completely

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DarlinEsteves DarlinEsteves

12-03-2021

Answer:

The answer is (y - 1)^3 = (y - 1) (y^2 + y + 1)

Step-by-step explanation:

[tex](y - 1)^{3} = (y - 1)( {y}^{2} + y \: \: 1 + {1}^{2} ) \\ \\(y - {1)}^{3} = (y - 1)( {y}^{2} + y + 1)[/tex]

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