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the length of a rectangle is 2 in longer than its width . if the perimeter of the rectangle is 32 in find its area

Respuesta :

Azieq
2w + 2 ( 2 + w ) = 32
2w + 4 + 2w = 32
4w = 28
w = 7

length = 2 + 7
= 9

area = 9 × 7
= 63 in^2

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