AshilaHusna AshilaHusna

11-11-2016
Mathematics

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Sebuah benda bergerak lurus dengan kecepatan 4km/jam selama 1 jam pertama.Pada jam kedua kecepatan dikurangi menjadi setengahnya ,demikian seterusnya,setiap jam kecepatan menjadi setengah kecepatan sdbelumnya.berapa km jarak yang dapat di capai benda tst?

Respuesta :

11-11-2016

A = 4 km/jam
r = 1/2
jarak terjauh
s = a/(1 - r)
s = 4/(1 - 1/2)
s = 8 km

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