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The critical angle of refraction for calcite is 68.4 when it forms a boundary with water. Use this information to determine the speed of light in Calcite. Assume the refractive index of water ,1.333, is less than the refractive index of calcite.

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Respuesta :

syed514
Using Snell's law with
N2=1.33 for water
N1 sin A1= N2 sin A2 = N2

N1= 1.33/sinA

so, the speed of light in clctie = (3*10^8 m/s) / 1.43


= 1*10^8 m/s

Answer:

The brainly answer is wrong.  If you're using it for Connexus it'll be wrong.  Good luck and do your own work.

Step-by-step explanation:

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