Answer:
See answer below
Explanation:
In this case, we are treating an alcohol with different reagents to give different products. In the picture below you have the draw of each product, and here, the explanation.
a) Hâ‚‚SOâ‚„: In this case, it will promote an E1 reaction forming an alkene as product.
b) NaH: In this case, it will promote an acid base reaction, and the final product will be an alcoxide.
c) HCl/ZnClâ‚‚: In this case, primary alcohols reacts with this reactive to form an alkyl halide.
d) HBr: Another reaction forming an alkyl halide with bromine in this case.
e) SOClâ‚‚: Similar to c), it will form an alkyl chloride.
f) PBr₃: Similar to d, forming an alkyl bromide.
g) TsCl: Here it will be a sustitution reaction, where tosilate replaces the OH
h) NaH/CH₃CH₂Br: In this case it will form an alcoxide and then, a larger alkyl.
i) TsCl/NaSH: First it will form a tosilate and then, the SH group. A sustitution reaction.
j) POCl₃: A sustitution reaction forming an alkyl chloride.
See picture below for drawings.
Hope this helps
