Answer:
the common velocity of the both objects after collision is 5.25 m/s.
Explanation:
Given;
mass of the first object, mâ = 5 kg
initial velocity of the first object, uâ = 6 m/s
mass of second object, mâ = 3 kg
initial velocity of the second object, uâ = 4 m/s
Let the common velocity of the both objects after collision = v
Apply the principle of conservation of linear momentum to determine the final velocity of both objects;
mâuâ + mâuâ = v(mâ + mâ)
5 x 6 Â + 3 x 4 = v(5 + 3)
30 + 12 = v(8)
42 = 8v
v = 42/8
v = 5.25 m/s
Therefore, the common velocity of the both objects after collision is 5.25 m/s.
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