A box has two balls, one white and one red. We select one ball, put it back in the box, and select a second ball (sampling with replacement). Let T be the event of getting the white ball twice, F the event of picking the white ball first, S the event of picking the white ball in the second drawing. Compute P ( T ) . Compute P ( T | F ) . Are T and F independent

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akiran007 akiran007 · Answer 1 · 2021-02-13T06:42:58+01:00

Answer:

P (T) = 1/4

P ( T | F ) = 1/2 = P(F)

The events are not independent.

Step-by-step explanation:

Let F the event of picking the white ball first

P (F)= 1/2 ( picking the white ball first)

Let T be the event of getting the white ball twice,

P (T) = P( getting white ball) * P( getting white ball)

=( 1/2)*(1/2)

= 1/4

Here P(T∩F) = P(T) because the probability of getting the white balls is the same as probability of getting the white ball first both the times.

P ( T | F ) = P (T∩F)/ P(F)

= (1/4)/ (1/2)

= (1/2)

= 1/2 = P(F)

For the events to be independent the conditional probability P ( T | F ) must be equal to P(T).

Hence the events are not independent.