
Answer:
x = 0.67 m
Explanation:
For this problem, let's use the projectile launch equations, as the jug goes through the bar, it comes out with horizontal speed vx = 1.3 m / s, which does not decrease as there is no friction.
Let's find the time or it takes to get to the floor
     y = y₀ + v_{oy} - ½ g t²
in this case I go = 0 and when I get to the floor y = 0
     0 = y₀ + 0 - ½ g t²
     t² = 2y₀ / g
     t² = 2 1.3 / 9.8 = 0.2653
     t = 0.515 s
now let's find the distance traveled in this time
     x = vx t
     x = 1.3  0.515
     x = 0.6696 m
     x = 0.67 m