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Copper sulfide is found written as both CuS and Cu2S. Why are there two forms for writing this chemical formula?

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This is an example of a combination reaction: CuS is the halfway stage, before the second copped atom joins the molecule.


Copper is a transition metal with two possible ionic states (copper I, or 1+, and copper II, or 2+).


This is a synthesis reaction and so the formula will continue changing until all the atoms have conglomerated.


One of the versions is a mistake, the correct form should be Cu2S.

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nish11235

Answer:

option 3

Explanation:

Copper is a transition metal with two possible ionic states (copper I, or 1+, and copper II, or 2+).

Eduard22sly

There are two forms for writing the chemical formula because copper is a transition metal with two possible ionic states (copper I, or 1+, and copper II, or 2+)

Copper is a transition metal with variable oxidation states. The oxidation states of copper is what determines the name of CuS and Cuâ‚‚S.

Now, we shall determine the oxidation states of copper in each compound.

For CuS:

CuS = 0

S = –2

Cu =?

Cu + S = 0

Cu + (–2) = 0

Cu – 2 = 0

Collect like terms

Cu = 0 + 2

Cu = +2

For Cuâ‚‚S:

Cuâ‚‚S = 0

S = –2

Cu =?

2Cu + S = 0

2Cu + (–2) = 0

2Cu – 2 = 0

Collect like terms

2Cu = 0 + 2

Divide both side by 2

Cu = 2/2

Cu = +1

From the calculations made above, we can see that copper has oxidation state of +2 in CuS and +1 in Cuâ‚‚S

Thus, we can conclude that Copper is a transition metal with two possible ionic states and this accounts for the different names of CuS and Cuâ‚‚S

Learn more: https://brainly.com/question/2510539

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