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the lengths of the sides of a triangle are consecutive even integers. one fourth of the perimeter is one less than the length of the shortest side. find the perimeter of the triangle.

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Answer:

  • 36

Step-by-step explanation:

Let the shortest side be x, the other sides are x + 2 and x + 4

Perimeter is:

  • P = x + (x + 2) + (x + 4) = 3x + 6

It is given that:

  • 1/4P = x - 1

Substitute and solve for x:

  • 1/4(3x + 6) = x - 1
  • 3x + 6 = 4x - 4
  • 4x - 3x = 6 + 4
  • x = 10

Perimeter is:

  • P = 3*10 + 6
  • P = 36

HERE,

the lengths of the sides of a triangle are consecutive even integers.

If one angle=a

other are=(a+2) and (a+4)

So,

perimeter(p) =a+a+2+a+4=3a+6

But,

one fourth of the perimeter is one less than the length of the shortest side.

[tex]\bold{\dfrac{1}{4}p=a-1 }[/tex]

so,

According to the question,

[tex]\tt{\dfrac{1}{4}(3a+6)=a-1 }[/tex]

[tex]\tt{\dfrac{3a+6}{4}=a-1 }[/tex]

[tex]\tt{4(a-1)=3a+6 }[/tex]

[tex]\tt{ 4a-4=3a+6 }[/tex]

[tex]\tt{4a-3a=6+4 }[/tex]

[tex]\bold{ a=10 }[/tex]

so,

Perimeter (p)=3×10+6=30+6=36

perimeter of the triangle is 36 .