
Answer:
A
Explanation:
Givens
d = 100 meters plus the depth of the well
d = 100 + x              where x is the depth of the well.
vi = 0 m/s              The object is dropped. It was not thrown.
t = 5 seconds
a = 9.81 m/s^2
formula
d = vi*t  +  1/2 a t^2
solution
100 + x = 0 + 1/2 * 9.81 * 5^2
100 + x = 122.625 Â Â Â Â Â Â Subtract 100 from both sides
x = 122.625 - 100
x = 22.6 Â m
The well is 22.6 meters deep.