avamadam avamadam
  • 13-01-2021
  • Mathematics
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-6j^-8 over -2(j^3)^5

6j8 over 2j35 class=
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Respuesta :

mathstudent55
mathstudent55 mathstudent55
  • 13-01-2021

Answer:

[tex] 3j^7 [/tex]

Step-by-step explanation:

[tex] \dfrac{-6j^{-8}}{-2(j^{-3})^5} = [/tex]

[tex] = \dfrac{-6j^{-8}}{-2j^{-15}} [/tex]

[tex] = 3j^{-8 - (-15)} [/tex]

[tex] = 3j^7 [/tex]

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