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A pitcher threw a baseball straight up at 35.8 meters per second. What was the ball's velocity after 2.50 seconds? (Note that, although the baseball is still climbing, gravity is accelerating it downward.)

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Answer:

The velocity after 2.5 seconds is 11.3 m/s

Explanation:

Given;

u = 35.8 m/s

t = 2.50s

g = 9.8 m/s^2

Mathematically;

V = U-gt

Substituting these values;

V = 35.8-2.5(9.8)

V = 35.8-24.5

V = 11.3 m/s

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